Question

the positive square root of 11 root 7 + 28 is

Answer 1

11×√(7)+28
=57.1032644217

Answer 2

The positive square root of $\sqrt{11\sqrt{7} + 28}$  is  $\sqrt[4]{7}\sqrt{11 + 4\sqrt{7}}$.

Step-by-step explanation:

Given,

= $\sqrt{11\sqrt{7} + 28}$

Now according to the problem,

= $\sqrt{11\sqrt{7} + 28}$

= $\sqrt{11\sqrt{7} + (4)(7)}$

= $\sqrt{11\sqrt{7} + (4)(\sqrt{7})^{2}}$

= $\sqrt{\sqrt{7}(11 + 4\sqrt{7})}$

= $\sqrt{\sqrt{7}}\sqrt{11 + 4\sqrt{7}}$

= $\sqrt[4]{7}\sqrt{11 + 4\sqrt{7}}$

Hence, the positive square root of $\sqrt{11\sqrt{7} + 28}$  is  $\sqrt[4]{7}\sqrt{11 + 4\sqrt{7}}$.

Learn more about positive square root

https://brainly.in/question/9068612

More about positive square root

https://brainly.in/question/7360767

#SPJ3