Question

the positive square root of 7 + root 48 is what

Answer 1

7+√48 = 7+√4×4×3 = 7+4√3
let it is the square of a+√b. (there must be in that format or you can see from the options also. All are in a+√b format)
so (a+√b)² = 7+4√3(a+√b)² = a²+b + 2a√b = 7+4√3
comparing the terms,2a√b = 4√3⇒ a√b = 2√3a=2, b=3and it satisfies a²+b = 7
So the required number is a+√b = 2+√3
or
We have 7+√48 
             = 4+3+√4×4×3
             = 2²+ (√3)²+2*2*√3
             = (2+ √3)²
Hence the square root is +(2+√3)

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Answer 2

Answer:

Step-by-step explanation:

7+√48 = 7+√4×4×3 = 7+4√3

let it is the square of a+√b. (there must be in that format or you can see from the options also. All are in a+√b format)

so (a+√b)² = 7+4√3(a+√b)² = a²+b + 2a√b = 7+4√3

comparing the terms,2a√b = 4√3⇒ a√b = 2√3a=2, b=3and it satisfies a²+b = 7

So the required number is a+√b = 2+√3

or

We have 7+√48 

             = 4+3+√4×4×3

             = 2²+ (√3)²+2*2*√3

             = (2+ √3)²

Hence the square root is (2+√3)