The positive value of K for which both the equations x2 + Kx + 64 =0 and
x
2
-8x+K=0 have real roots, is
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Answer:
k = 4 (or) - 4
Step-by-step explanation:
Given Quadratic Equation is x^2 - kx + 4 = 0.
Comparing Equation with ax^2 + bx + c = 0
a = 1, b = -k, c = 4.
Given that the Equation has real roots.
D = 0
b^2 - 4ac = 0
(-k)^2 - 4(1)(4) = 0
k^2 - 16 = 0
k^2 = 16
k = 4 (or) - 4.
Hope this helps!
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