The possible correct set of four quantum numbers for the valence electron of sodium atom (Z = 11) is
O 3, 2, 1,-
2
0 3, 1, 0, + 1 /
O 3+
3,0,0,+
2
1
4,0,0,+
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Answer:
E.C of Rubidium is (Z=37) = 1s
2
2s
2
2p
6
3s
2
3p
6
4s
2
3d
10
4p
6
5s
1
The valence electron is in 5s orbital.
Its 4 quantum numbers are- n=5,l=0,m=0,s=+
2
1
Therefore, the correct option is C
Explanation:
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