Question

the possible L values for a given n values are.....
1) 0 to (n-1)
2) 0 to n
3) 1 to n
4) 1 to ( n-1)​

Answer 1

n is principal quantum number and l is azimuthal quantum number.

l cannot be greater than n.

Therefore the possible value of l for a given n is 0 to (n-1).

So option 1 is correct answer.

Answer 2

$\huge \red{0 \: to \: (n - 1)}$