Question

The possible values of m in the Pythagorean triplet given below can be
(2m, m square-1, m square+1):
Options-
0
<0
>1
<1

Answer 1

Answer:

Let a=m2−1b=2mc=m2+1

using pythagoras theorem, a2+b2=c2

So, (m2−1)2+4m2=(m2+1)2

m4+1−2m2+4m2=(m2+1)2m4+2m2+1=(m2+1)2(m2+1)2=(m2+1)2

Since LHS=RHS , we can say that a,b,c always form pythagorean triplet.

Step-by-step explanation:

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