Question

the potential at 0.5 Å from a proton is​

Answer 1

hey mate, here is your answer.

Answer 2

Answer:

The potential at $0.5\AA$ from a proton measured is $28.8V$.

Explanation:

Given,

The distance from a proton, r = $0.5\AA$

Convert $\AA$ in m

• $1 \AA$ = $10^{-10}m$
• $0.5\AA$ = $0.5\times 10^{-10} m$

The potential of a given point, V =?

As we know,

• The potential at a given point can be calculated by the formula given below:
• V = $\frac{kq}{r}$        -------equation (1)

Here,

• k = The coulombs constant = $9\times 10^{9}$
• q = The charge of a proton = $1.6\times 10^{-19}C$
• r = The distance from a proton

After putting the values in equation (1), we get:

• V = $\frac{9\times 10^{9}\times 1.6\times 10^{-19} }{0.5\times 10^{-10} }$
• V = $28.8V$

Hence, the potential of a given point, V = $28.8V$.