Question

The potential at a point due to a charge of 4 × 10-7C

located 9cm is ………....................... V.​

Answer 1

Given :

Charge , q = 4 * 1$0^{-7}$ C

Distance , r = 9 cm = 0.09 m

To find :

The potential due to the given charge at the point located on 0.09 m from charge .

Solution :

Potential due to a charge =  ( k * q ) / r

where , k is a constant equal to 9.0 * 1$0^{9}$ N$m^2$/$C^{2}$ ,

q is charge ,

and , r is distance .

now ,

potential = ( 9.0 * 1$0^{9}$ *  4 * 1$0^{-7}$ ) / 0.09

=> potential = 4 * 1$0^{4}$ V

The potential due to the given charge at the point located on 0.09 m from charge is 4 * 1$0^{4}$ V .