Physics, asked by jatinagrawal4431, 9 months ago

The potential at a point due to a charge of 5×70C located 10 cm away is

Answers

Answered by CHITRANSHI7060

0

Answer:

given: 350C____charge 'q'
distance: 10cm____10×10^-3m
k = 9×10^9

Explanation:

v = kQ/r

= 9×10^9×350/10×10^-3

= 3.15×10^14

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