The potential at a point due to an electric dipole will be maximum and minimum when the angles between the axis of the dipole and the line joining the point to the dipole are respectively
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Answer:
V=pcosθr2. If θ=0∘ then Va=max.
If θ=180∘ then Ve=min.
Explanation:
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0° and 180° are the angles at which potential will be max and min respectively.
- The potential at a point due to an electric dipole is V = PEcos∅/r² where, P = Dipole E = Electric field and ∅ = Angle between dipole and electric field
- When ∅ = 0° ,
V = PEcos0/r²
V = PE/r² ( cos0 = 1) which is maximum potential.
- When ∅ = 180° ,
V = PEcos0/r²
V = -PE/r² ( cos180 = -1) which is mInimum potential.
Therefore, at 0° and 180° are the angles at which potential will be max and min respectively.
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