Question

The potential at a point due to charge of 5×10-7C located 10cm away is​

Answer 1

V= k×q×mue

9×10^9×5×10^-7×10

45×10^10×10^-7

45×10^3

4.5×10^2 V

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Answer 2

Given:

Charge, Q = 5 × 10⁻⁷ C

The distance between point and the given charge, r = 10 cm = 0.1 m

To Find:

The electric potential at a point 10 cm away from the charge.

Calculation:

- We know that electric potential at a point is given by the formula:

V = k × Q/r

⇒ V = 9 × 10⁹ × 5 × 10⁻⁷ / 0.1

⇒ V = 45 × 10² / 0.1

⇒ V = 45000 Volts or 45 kV

- So, the electric potential at that point is 45 kV.