Question

the potential barrier for germanium pn junction is 0.3V . if the width of the depletion layer is 1 micron then field strength at the junction is​

Answer 1

Given:

Potential barrier for germanium = 0.3$V$

Width for depletion layer       = 1 micron

To Find:

Electric Field at the junction = ?

Solution:

Electric- field intensity: is the force that is experience by charge or pole in the presence of electric field.

Electric-field intensity expressed by-

$E = \dfrac{V}{d}$

V = Potential in volt

d = Distance in metre

V = 0.7 volts

d = 1 micron = 1 × $10^{-6}$ metre

$E = \dfrac{0.7}{10^{-6} }$

E   =  7 × $10^{5}$  $\frac{V}{m}$

So field strength is  7 × $10^{5}$  $\frac{V}{m}$