The potential difference across the terminals of a load is 25 V when it draws a current of 2 A from the source. If the potential difference is increased to 50 V, what is the current drawn by the same load?
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Answer:
4 A
Explanation:
R = V/I = 25/2 = 12.5 ohms
I = V/R = 50/12.5 = 4 ampere
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