the potential difference across the terminals of the bateery shown in fig is
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Explanation:
The current flowing to the circuit
i = V / R
Total equivalent Resistance is = 4 + 1 = 5 ohm ( because they are in series )
So
Given , V = 10 volt
i = 10 / 5 = 2 ampere
Potential difference across the terminal of battery ( V ) =
I R ( external resistance )
= 2 × 4 = 8 volt
So , the potential is 8 volt across the terminal of battery .
Thank you
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