Physics, asked by yogirajmaliya6805, 1 year ago

The potential difference applied across a given resistor is altered so that the heat produced per second increases by a factor of 9. by what factor does the apllied potential difference change?

Answers

Answered by Shaizakincsem
101

Let original Potential difference applied is V and original Heat Produced is H. 

Then, H = V^2t\over R…………(1)

New potential difference is V' and Heat Produced after change is H'.

Then, 

H' = {V'^2t\over R} …………(2)

According To question,

H' = 9H

=> {V'^2t\over R} =9\times {V^2t\over R} 

=> V'2 = 9V2

=> V' = 3V

So potential difference is increased by a factor 3.

Answered by dhabhaikhushi
2

Answer:

Explanation:

Secondary School Physics 13+7 pts

The potential difference applied across a given resistor is altered so that the heat produced per second increases by a factor of 9. by what factor does the apllied potential difference change?

Report by Yogirajmaliya6805 12.02.2018

Answers

DhabhaikhushiAmbitious

Know the answer? Add it here!

Shaizakincsem

ShaizakincsemSamaritan

Let original Potential difference applied is V and original Heat Produced is H.

Then, H = V^2t\over R…………(1)

New potential difference is V' and Heat Produced after change is H'.

Then,

H' = {V'^2t\over R} …………(2)

According To question,

H' = 9H

=> {V'^2t\over R} =9\times {V^2t\over R}

=> V'2 = 9V2

=> V' = 3V

So potential difference is increased by a factor 3.

Similar questions