The potential difference applied to an x-ray tube is 5 kilo volt and the current through it is 3.2 milliampere then find the number of electrons striking
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Solution :
n=Iten=Ite
=3.2×10−3×11.6×10−19=3.2×10−3×11.6×10−19
=2×1016
n=Iten=Ite
=3.2×10−3×11.6×10−19=3.2×10−3×11.6×10−19
=2×1016
Answered by
1
Answer:
=> I = q/t =ne/t
At, time =1s
=> n = I/e = (3.2×10^-3)/(1.6×10^-19) = 2×10^16
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