Question

The potential difference applied to an X-ray
tube is 5 kV and the current through it
is 3.2 mA. Then the number of electrons
striking the target per second is
(A) 5 x 106
(B) 2 x 1016
(C) 1 x 1017
(D) 4 x 1018​

Answer 1

Explanation:

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PHYSICS

Asked on December 20, 2019 byDhruv Vasave

The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. What is the number of electrons striking the target per second ?

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ANSWER

solution We know that,

I=△t△θ

Here, △θ= (no of electrons striking in 

time interval △t) (electronic charge)

I=3.2mA,△t=Is and electronic

charge = 1.0×10−19c ,so,

3.2×10−3=(1.6×10−19)−1△n(1)

1.6×10193.2×10−3=△n

△n=2×1016

where △n→ No. of electrons striking

per sec.