Question

the potential difference at poin A is 10 v and at B -10v then find workdone to move a charge of 1×10⁶ colomb from point A to B​

Answer 1

The amount of charge Q, that flows between two points at potential difference (V=10) is $\sf \: 1×10^6$C. Thus, the amount of work W, done and moving the charge is,

$\sf \: { \red{w = vq}} \\ \sf \: w = 1 \times 10 {}^{6} \times 10 \\ \sf \: w = {10}^{7} \: J$

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