the potential difference b/w the terminals of an electric heater is 60V when it draws a current of 4A from the source. What will the heater draw if the potential difference is increased to 120V ?
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we have to remember the fact that for a given material the resistance is constant. so the resistance is same throughout
We know the equation V= I*R
where,
V= potential difference
I= current
R= resistance
it is given that V= 60 V
I= 4A
applying the equation, R= V/I
R= 60 /4
R= 15Ω
in next condition,
V= 120 V
I= V/R
I= 120 / 15
I= 8 A
We know the equation V= I*R
where,
V= potential difference
I= current
R= resistance
it is given that V= 60 V
I= 4A
applying the equation, R= V/I
R= 60 /4
R= 15Ω
in next condition,
V= 120 V
I= V/R
I= 120 / 15
I= 8 A
Answered by
2
Answer:
The current through the heater becomes 8 A.
Explanation:
Given,
The potential difference between the terminals of an electric heater is 60 V.
Current of 4 A is drawn from the source.
To find: What current will the heater draw if the potential difference is increased to 120 V
Solution:
According to Ohm's law, Potential difference is directly proportional to current.
i.e V I
or, V = iR
here, V = 60 V and i = 4 A
Substituting the values,
R = V / i = 60 / 4 = 15 Ω
Now, V is increased to 120 V.
Again using ohm's law,
i = V / R = 120 / 15 = 8 A
Therefore, The current through the heater becomes 8 A.
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