Question

The potential difference between point A and B in the figure is
A. 20/7 V
B.40/7 V
C.10/7 V
D. Zero

Answer 1

Answer:

first we find current i1and i2 from equation 1 and 2 by following kirchhoff's law. similarly i find potential difference by equation.In equation, when i go in the direction of current then take "-ve" but when we go opposite to current direction then take +ve sign in all equation.

Answer 2

The potential difference between A and B is zero (D).

Given:

The voltage of the baterry= 10V

8Ω,6Ω and 4Ω, 3Ω are in series each other and in parallel respectively.

To Find:

The potential difference between A and B.

Solution:

The given circuit is an example of Wheatstone Bridge.

In Wheatstone Bridge, $\frac{P}{Q}=\frac{R}{S}$ [Refer to the image]

Then, $V_A=V_B$

Here in the P= 4Ω Q=3Ω R= 8Ω S= 6Ω

$\frac{4}{3}= \frac{8}{6}$

So $V_A=V_B$

Hence, the potential difference between A and B is 0.

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