Question

the potential difference between the ends of the wire of resistance 1ohm is doubled the electric power across the wire will_________by_________._​

Answer 1

It will increase by a multiple of 4

Explanation:

Let us take P.d. as 1 V , so as per the formula:

P=V^2/R....so Power=(1)^2/1...so P=1W

now let us double the P.d.

So, P=V^2/R...

P=(2)^2/1=4/1=4W

So we can conclude that if we double the P.d. through a wire having Resistance as 1 Ohm....the Power increases with a multiple of 4...thank you!

Answer 2

Answer:

It will increase by 4 times.

Explanation:

let the potential difference between the ends of the wire = V.

and resistance = 1Ω.

as we know that power, P = V^2/R

so if the potential difference is doubled then new voltage will be

V' = 2V.

new power, P' = V'^2/R

= (2V)^2/R

= 4V^2/R

P' = 4P (P = V^2/R)

So the power will increase by 4.