Question

The potential difference between the points A and B in the given circuit will be



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Answer 1

Answer:

By KVL

V

A

+3I

1

+4−3I

2

=V

B

KVL(1)

2−3I

1

−2I

1

=0

5I

1

=2

I

1

=

5

2

=0.4

KVl(2)

4−3I

2

−5I

2

=0

8I

2

=4

I

2

=0.5

V

A

−V

B

=4−3I

1

+3I

2

=4−3(I

1

−I

2

)

V

A

−V

B

=4−3(−0.1)=4.3

We get, V

A

−V=4.3