Question

The potential difference between the terminal of a battery in open circuit is 2.2 V when
connected across a resistance of 6 the potential falls to 1.8 V. The internal resistance of the

battery is
A) 1. 33
B) 1.11
C) 1
D) 1.2​

Answer 1

Answer:

Answer is Option (A) 1.33

Explanation:

First find the load current:

I=1.8/6 = 0.3A.

Find the voltage drop of the battery internal resistance:

2.2V-1.8V= 0.4V

Now you know the current and voltage on the internal resistance:

R=V/I = 0.4/0.3=1.333 ohms