The potential difference between the terminals of a cell is 40V when 10A are being drawn
and 46V when 4 A are being drawn. The emf of the cell and its internal resistance are
respectively,
(A) 50V, 10
(B) 45V, 1.20
(C) 55V, 80
(D) 6.0V, 1.2
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Answer:
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Explanation:
Given: V=12V, Resistance of A=4Ω, Resistance of B=6Ω, Internal battery resistance =2Ω
(i) Total Resistance =4+6+2=12Ω
I (current in circuit)=
Totalresistance
e.m.f.
=
12
12
=1amp
(ii) Voltage drop Ir=1×2=2volt
Terminal Voltage = emf - Voltage drop
=12−2=10 volts
(iii) Potential difference across 6Ω=IR
=1×6=6V
(iv) Energy spent =I
2
Rt
=(1)
2
×4×60=240J
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