Physics, asked by anilverma470, 9 months ago

The potential difference between two points in vacuum is Vo . If vacuum is replaced by a medium of dielectric constant K, the new value of potential difference will be_____________. ¿?

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Answers

Answered by aristocles
2

Answer:

Potential difference between two points in other medium is given as

\Delta V' = \frac{V_o}{k}

Explanation:

As we know the relation between electric field and voltage difference between two points as

\Delta V = E.d

so as the medium is changed by other dielectric medium then we have

E_{med} = \frac{E}{k}

so we have

\Delta V' = E_{med} d

now divide above two equations

\frac{\Delta V}{\Delta V'} = \frac{E}{E_{med}}

now we have

\frac{\Delta V}{\Delta V'} = k

so we have

\Delta V' = \frac{\Delta V}{k}

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Topic : Electric potential

https://brainly.in/question/2082923

Answered by shrutisharma4567
44

Explanation:

The potential always gets multiplied with potential in case battery is not there

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