Question

the potential difference of 250 volt is applied across the resistance of 1000-2 is an electric iron find current and heat produced in 12 seconds
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Answer 1

● Question :

The potential difference of 250 volt is applied across the resistance of 1000 ohm in an electric iron. Find the current and heat produced in 12 seconds.

● To Find :

• The Current in 12 seconds.

• The Heat produced in 12 seconds.

● Given :

• Potential Difference = 250 V

• Resistance of the Electric Iron = 1000 ohm.

• Time = 12 seconds

● We Know :

Formula for Potential Difference :

$\purple{\sf{\underline{\boxed{V = I \times R}}}}$

Where,

• V = Potential Difference

• I = Current

• R = Resistance

Formula for Heat Produced :

$\blue{\sf{\underline{\boxed{H = I^{2} \times R \times t}}}}$

Where,

• H = Heat Produced

• I = Current

• R = Resistance

• t = Time

● Concept :

From the ohm's law i.e, $\sf{V = I \times R}$ , we get the formula for current as :

$\implies \purple{\sf{Current (I) = \dfrac{Potential Difference (V)}{Resistance}}}$

To find the Heat produced , first we have to find the Current given to the electric iron.

● Solution :

To find the Current :

Given :

• Resistance = 1000 ohm

• Potential Difference = 250 V

Using the formula for Current , and Substituting the values in it , we get :

$\implies \sf{Current (I) = \dfrac{Potential Difference (V)}{Resistance}} \\ \\ \\ \implies \sf{Current (I) = \dfrac{250 V}{1000 \Omega}} \\ \\ \\ \implies \sf{Current (I) = \dfrac{1V}{4 \Omega}} \\ \\ \\ \implies \sf{Current (I) = 0.25 A} \\ \\ \therefore \purple{\sf{Current (I) = 0.25 A}}$

Hence , the Current given to the electric iron is 0.25 A.

To find the Heat Produced :

Given :

• Resistance = 1000 Ohm

• Current = 0.25 A

• Time = 12 s

Using the formula and substituting the values in it , we get :

$\implies \sf{H = I^{2} \times R \times t} \\ \\ \\ \implies \sf{H = 0.25^{2} \times 1000 \times 12} \\ \\ \\ \implies \sf{H = \bigg(\dfrac{25}{100}\bigg)^{2} \times 1000 \times 12} \\ \\ \\ \implies \sf{H = \dfrac{625}{10000} \times 1000 \times 12} \\ \\ \\ \implies \sf{H = \dfrac{625}{10} \times 12} \\ \\ \\ \implies \sf{H = \dfrac{625}{5} \times 6} \\ \\ \\ \implies \sf{H = 125 \times 6} \\ \\ \\ \implies \sf{H = 750 J} \\ \\ \\ \therefore \purple{\sf{H = 750 J}}$

Hence , the Heat Produced is 750 J