Question

The potential difference of a cell in an open circuit is 6 V which falls to 4 V when a current of 2 A is drawn from the cell . Calculate the emf and the internal resistance of the cell .

Answer 1

hloo frnd and your answer is as follows.....

According to the question:
Electromotive Force (EMF) = 6V (As EMF is potential difference when no current is flown through the circuit , ie. Open Circuit )
Terminal Potential Difference(TPD) = 4V  (As TPD is potential difference when a certain amount of current is flown)
Using Formula: 
EMF = TPD + I*r  (Where I= Current flowing through the circuit    ,    r = Internal resistance of the cell )
6 = 4 + 2*r
2*r = 2
r = 1 Ohm
​​​
Therefore,  Emf of Cell = 6V      Internal Resistance = 1 Ohm

hope it may helps u....☺☺

Answer 2

Explanation:

This question is from Emf

I hope that it will helps you friends,