the potential difference of a circuit is doubled by what factor does the power change in the circuit
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we can use P=V^2*R
So here V is the potential difference
So if it is doubled the new V becomes 2V and by this relation P=4*V^2*R
hence it is quadrupled (4times)
So here V is the potential difference
So if it is doubled the new V becomes 2V and by this relation P=4*V^2*R
hence it is quadrupled (4times)
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