Physics, asked by mkw, 1 year ago

the potential difference of a circuit is doubled by what factor does the power change in the circuit

Answers

Answered by utsavkakkadp3kujm

we can use P=V^2*R
So here V is the potential difference
So if it is doubled the new V becomes 2V and by this relation P=4*V^2*R
hence it is quadrupled (4times)

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