The potential difference of a circuit is doubled. By what factor does the power change? (How to know whether to use P=V^2/R or P=VI
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Explanation:
you've did something wrong. I guess you want to p=v^2/R and p=I^2R
so as I know for parallel circuit the v is same and for series I will be same...so for first case you've use the first formula and for second you've to use the second .
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