The potential energy of a 1 kg particle free to move along the X-axis is given by U(x)
XA
4
J. The total mechanical energy of the
2
particle is 2). Then, maximum speed (in ms-l) is :-
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The potential energy of a 1kg particle free to move along the x- axis is given by
V(x)=(x44-x22)J. The total mechainical energy of the particle is 2J..
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