Physics, asked by Humairah28, 3 months ago

The potential energy of a 1 kg particle,free to move along x-axiz is given by U(x) = {x^3/3 - x^2/2} J. Its mechanical energy is 2J. Its maximum speed is _____ m/s​

Answers

Answered by gaytrigaydhane2003
0

Answer:

It's mechanical energy is 2j then the its maximum speed is

3 \div  \sqrt[]{2}

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