Question

The potential energy of a 100 kg block 10 m along a 30° inclined plane
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Answer 1

Dear Student,

◆ Answer -

PE = 4900 J

● Explaination -

# Given -

m = 100 kg

s = 10 m

θ = 30°

# Solution -

Potential energy on inclined plane is given by -

PE = mgh

PE = mgssinθ

PE = 100 × 9.8 × 10 × sin30°

PE = 9800 × 0.5

PE = 4900 J

Therefore, potential energy of the block will be 4900 J at inclined plane.

Hope that is helpful to you...

Answer 2

The potential energy(PE) of the block will be "4900 J ".

Step-by-step explanation

Given

mass(m) = 100 kg, s = 10 m and θ = 30°

To find, potential energy(PE) = ?

Potential energy on inclined plane, PE = mgh

∴ PE = mgssinθ

PE = 100 × 9.8 × 10 × sin30°

= 9800 × 0.5

= 4900 J

Hence, the potential energy(PE) of the block will be 4900 J.