Question

The potential energy of a 2 kg particle free to move along X axis is given by V(X) = (x^3/3 - x^2/2)J. The total mechanical energy of the particle is 4J. Maximum speed is
a) 1/√2. b)√2. C)3/√2 d) 5/√6

plss ans the que as fast as possible​

Answer 1

Answer:

5/root6

Hope this helps you...

Pls mark me brainliest...