The potential energy of a body of mass 0.5 kg
increases by 100 J when it is taken to the top of
a tower from ground. If force of gravity on 1 kg
is 10 N, what is the height of the tower ?
Answers
Answered by
24
Answer:
20m.
EXPLANATION:-
GIVEN:-
P.E = 100 J
Mass = 0.5 kg
NOW, force of gravity = mg
so, mg = 10N for 1 kg mass
so, mg = 5N for 0.5 kg mass
NOW,
=> P.E = mgh
=> 100J = 5N × h
=> 100 Nm = 5N × h
=> h = 20 m.
- ANSWER:- 20 m
Answered by
0
Answer
Given that,
Mass of body M=0.5kg
Potential energy P.E=100J
Force of gravity on 1 kg is 10 N
Now,
F=mg
10=1×g
g=10m/s²
Now, change in Potential energy
=mg(h² −h¹)
=mg(h−0)
=mgh
Now, the height is
100=mgh
h= 1
h=20m
Hence, the height of the tower is 20 m
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