Question

The potential energy of a charged parallel plate capacitor is Uo. If a slab of dielectric constant k is inserted between the plates then find the new potential energy of capacitor

Answer 1

Answer:I have attached the picture of solution.

Explanation:the only logic is that capacitance is directly proportional to dielectric constant k so only c changes to kc Everything else would be same.

Answer 2

Answer:

U0/K

Explanation:

When a dielectric slab of dielectric constant K is inserted between the plates of charged parallel plate capacitor, then.

capacity becomes c=KC

potential becomes v=V/K

energy =U/K

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