Physics, asked by umaimakhalid5879, 10 months ago

The potential energy of a conservative force field is given by U=ax^(2)-bx where, a and b are positive constants. Find the equilibrium position and discuss whether the equilibrium is stable, unstable or neutral.

Answers

Answered by ParvezShere
2

The position of equilibrium is b/2a and the equilibrium is stable.

Given the potential energy of a conservative force field , U = ax² - bx where a and b are positive constant.

F = -dU/dx = force is equal to the differential of potential energy w.r.t x.

F = -2ax + b

For equilibrium F = 0

=> -2ax + b = 0

=> x = b/2a

d²U/dx² = 2a ( positive as a is a positive constant ), this means that b/2a is point of minima and the equilibrium is stable.

Similar questions