Question

The potential energy of a particle executing SHM with amplitude A is Eat the

extreme position. What is its kinetic energy at y=A/2?

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Answer 1

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Refer to the attachment

Explanation:

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Answer 2

""" ❤️ Answer ❤️ """

TotalenergyisSHME=

2

1

mw

2

a

2

(wherea=amplitude)

potentialenergyU=

2

1

mw

2

(a

2

−y

2

)

=E−

2

1

mw

2

y

2

Wheny=

2

a

U=E−

2

1

mw

2

(

4

a 2

)

=E−

4

E

=

4

3E

Hence,

option (A) is correct answer.