Question

The potential energy of a particle in a field is
U-, b
where a and b are constants.
The value of rin terms of a and b where the
force on the particle is 0 is equal to **
b
where x is?​

Answer 1

Answer:

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Explanation:

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Answer 2

for equilibrium dU/ dr = 0

-2A/r³ + B/r² = 0 r = 2A / B

for stable equilibrium d²U /dr² should be positive for the value of r.

here d²U / dr² = 6A/r⁴ – 2B/r³ is +ve value for r = 2A / B So.