Question

The potential energy of a particle of mass 100g moving along x axis

Answer 1

Question is incomplete, it would be possible like The potential energy of a particle of mass 100g moving along x axis is U=5x(x-4), where x is in metres. What is the period of oscillation?  

Ans. F=-dU/dx, given U=5x(x-4)

F= - 10(x-2)

F= - 10X

We know F= -Kx;

Therefore, spring constant, K= 10.

Time period, T= 2*pi*(m/k)^1/2 , where m is the mass in kg.

Putting all the values , finally, T = pi/5 seconds.

Answer 2

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