Question

The potential energy of a particle of mass 4 kg is given as

U = -4x² + 8x⁴

, where x is the position of the particle along

positive x-axis from origin. The particle moves along x-axis

Then

(A) the potential energy of the particle is maximum at x = 0

(B) the potential energy of the particle is minimum at
x = ½


(C) the time period of small oscillations of the particle about a

point of minima is 2π s

(D) the time period of small oscillations of the particle about

a point of minima is π s​

Answer 1

Explanation:

The potential energy of a particle of mass 4 kg is given as

U = -4x² + 8x⁴

, where x is the position of the particle along

positive x-axis from origin. The particle moves along x-axis

Then

(A) the potential energy of the particle is maximum at x = 0

(B) the potential energy of the particle is minimum at

x = ½

(C) the time period of small oscillations of the particle about a

point of minima is 2π s

(D) the time period of small oscillations of the particle about

a point of minima is π s