Physics, asked by hritikdgmailcom5554, 1 year ago

The potential energy of a particle (U_{x}) executing S.H.M. is given by(a) U_{x}=\frac{k}{2}(x-a)^{2}(b) U_{x}=k_{1}x+k_{2}x^{2}+k_{3}x^{3}(c) U_{x}=Ae^{-bx}(d) U_{x}=a\ constant

Answers

Answered by Nitika07
0

this question is impossible to solve

Similar questions