the potential energy of a particle varies with distance 'x' from a fixed point as V=P(x)^1/2 ÷ x+Q, where P and Q are constants. Then the dimensions of PQ are:
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Answer is a. M^1 L^5/2 T^-2 ...
As potential energy has dimensionM^1 L^2T^-2
By applying equation analysis we get the dimension of PQ ....
Answer is a. M^1 L^5/2 T^-2 ...
As potential energy has dimensionM^1 L^2T^-2
By applying equation analysis we get the dimension of PQ ....
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