Question

The potential energy of a projectile at its maximum height is equal to its kinetic energy there. If the
velocity of projection is 20 m/s. It's time of flight is​

Answer 1

Answer:

2s

Explanation:

22–√s

12s

12–√s

Answer :

B

Solution :

P.E=K.E⇒12mu2sin2θ=12mu2sin2θ