The potential energy of a projectile at its
maximum height is equal to its kinetic energy
there. Its range for velocity of projection is
1. u^2/2g
2.u^2/g
3.2u^2/g
4.2u/g
Answers
Answered by
0
Explanation:
Mg(
2g
u
2
sin
2
θ
)=
2
1
Mu
2
cos
2
θ
tan
2
θ=1
θ=45
∘
T=
g
2usinθ
T=
10
2
2×20
=2
2
seconds
Answered by
0
ANSWER
Mg(
2g
u
2
sin
2
θ
)=
2
1
Mu
2
cos
2
θ
tan
2
θ=1
θ=45
∘
T=
g
2usinθ
T=
10
2
2×20
=2
2
seconds
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