Question

The potential energy of a spring when stretched by 2
cm is U. If the spring is stretched by 4 cm, the potential
energy stored in it is
(1) 4U
(2) 2U
(3) 8U
(4) 16U​

Answer 1

Answer:

Correct option is

C

16U

U =

2

1

K(2)

2

and U

=

2

1

K(8)

2

⇒

U

U

= (

2

8

)

2

= 16 ⇒ U

= 16U

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