The potential energy of a spring when stretched by 2
cm is U. If the spring is stretched by 4 cm, the potential
energy stored in it is
(1) 4U
(2) 2U
(3) 8U
(4) 16U
Answers
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0
Answer:
Correct option is
C
16U
U =
2
1
K(2)
2
and U
=
2
1
K(8)
2
⇒
U
U
= (
2
8
)
2
= 16 ⇒ U
= 16U
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