Question

The potential energy of a spring when stretched through 10cm is 5j

Answer 1

Explanation:

Given P.E to stretch throgh 'x' is

1212kx2=10Jkx2=10J

To stretch through additonal distance 'x'

1212k[(2s)2−s2]=3×12k[(2s)2−s2]=3×12×ks2×ks2

=3×10J=3×10J

=30J

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