Question

The Potential energy of a spring when stretched through 10cm is 5J. The work done to stretch the spring through an additional distance of 10cm is

(A) 20J
(B) 15J
(C) 25J
(D) 10J​

Answer 1

Answer:

30J

Explanation:

F=

2

1

kx

2

In the first case, F=10J is required to stretch the spring by length x

10=

2

1

kx

2

F is the force required to stretch the spring by an additional length x

F=

2

1

k(2x)

2

=4×10=40J

Therefore additional force required is 40−10=30J

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