Question

the potential energy of a system given by u=K/r2. Find the state of equilibrium of the system​

Answer 1

Answer:

In a conservative field

F=−

dx

dU

∴F=−

dx

d

(ax

2

−bx)=b−2ax

For equilibrium F=0

or b−2ax=0∴x=

2a

b

From the given equation we can see that

dx

2

d

2

U

=2a (positive), i.e., U is minimum.

Therefore, x=

2a

b

is the stable equilibrium position.