Question

The potential energy of an electron in the h-atom is –6.8 ev. In which excited state, the electron is present?

Answer 1

The formula for calculating the potential energy of an electron is -13.6Z²/n where Z is the atomic number and n is the shell.

-6.8 = -13.6×1/n (since Z of H = 1)

n = 2

Since the electron is in the second shell and it was initially in the first shell, its in the first excited state.

Answer 2

Answer:

first

Explanation:

-6.8= -13.6*1/n

n=2

so initially in first excited state