The potential energy of ground state of h is 0 ihen the total energy of electrob in first exicited state is
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The total energy of any level in Hdrogen atom is E = -13.6/n2E
(ground state) = -13.6evE
(first exited state) = -13.6/4 ev
potential of ground state = -27.2evif potential of ground state is 0 then we have to add +27.2 , by this method wecan make ground state potential 0 ...now add this potential to energy of each state this will give the final energy of that state ...
E(first exited state) = -13.6/4 + 27.2 = 23.8ev
(ground state) = -13.6evE
(first exited state) = -13.6/4 ev
potential of ground state = -27.2evif potential of ground state is 0 then we have to add +27.2 , by this method wecan make ground state potential 0 ...now add this potential to energy of each state this will give the final energy of that state ...
E(first exited state) = -13.6/4 + 27.2 = 23.8ev
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